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  • Four equal masses, m each are placed at the corners of a square of length (l) as shown in the figure. The moment of inertia of the system about an axis passing through A and parallel to DB would be : <img alt="" src="https://cdn.entrance360.com/media/u

Four equal masses, m each are placed at the corners of a square of length (l) as shown in the figure. The moment of inertia of the system about an axis passing through A and parallel to DB would be :
 
Option: 1 2\; ml^{2}
Option: 2 3\; ml^{2}
Option: 3 ml^{2}  
Option: 4 \sqrt{3}\; ml^{2}

Answers (1)

best_answer

As we know

\text { Moment of inertia of point mass }=\text { mass } \times \text { (Perpendicular distance from axis) }^{2}

i.e I=mr^2

\begin{array}{l} I=\mathrm{m}(0)^{2}+\mathrm{m}(l \sqrt{2})^{2}+\mathrm{m}\left(\frac{l}{\sqrt{2}}\right)^{2}+\mathrm{m}\left(\frac{l}{\sqrt{2}}\right)^{2} \\ I=3 \mathrm{~m} l^{2} \end{array}

Posted by

avinash.dongre

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