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  • Gaseous N2O4 dissociates into gaseous NO2 according to the reaction <img alt="\mathrm{N_{2}O_{4}(g)\rightleftharpoons 2NO_{2}(g)}" src="https://entranceco

Gaseous N2O4 dissociates into gaseous NO2 according to the reaction

\mathrm{N_{2}O_{4}(g)\rightleftharpoons 2NO_{2}(g)}

At 300 K and 1 atm pressure, the degree of dissociation of N2O4 is 0.2. 

If one mole of N2O4 gas is contained in a vessel, then the density of the equilibrium mixture is :

Option: 1

1.56 g/L


Option: 2

3.11 g/L


Option: 3

4.56 g/L


Option: 4

6.22 g/L


Answers (1)

best_answer

                                   \mathrm{N_2O_4(g)\rightleftharpoons 2NO_2}

Moles at equilibrium    (1-0.2)                 (0.4)

                                    =0.8

\text{Molar mass of mixture}\mathrm{(M_{eff})} = \chi_{N_2O_4}\times 92 + \chi_{NO_2}\times 46


\therefore \mathrm{M_{eff}=\frac {0.8 \times 92 + 0.4 \times 46}{1.2} = 76.67}

\mathrm{\therefore d=\frac {P\times M_{eff}}{R T}= \frac{1 \times 76.67}{0.0821 \times 300} = 3.11\ \frac{g}{L}}

Hence, the correct answer is Option (2)

Posted by

Divya Prakash Singh

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