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A bag contains 4 red and 6 black balls. A ball is drawn at random from the bag, itscolour is observed and this ball along with two additional balls of the same colour arereturned to the bag. If now a ball is drawn at random from the bag, then the probability that this drawn ball is red, is :

  • Option 1)

    \frac{3}{4}

  • Option 2)

    \frac{3}{10}

  • Option 3)

    \frac{2}{5}

  • Option 4)

    \frac{1}{5}

 

Answers (1)

best_answer

 

P(R)= 4/10\cdot 6/12+ 6/10\cdot 4/12=2/5

 

Multiplication Theorem of Probability -

If A and B are any two events then 

P\left ( A\cap B \right )= P\left ( B \right )\cdot P\left ( \frac{A}{B} \right )


 

- wherein

where B\neq \phi

 

 


Option 1)

\frac{3}{4}

Option 2)

\frac{3}{10}

Option 3)

\frac{2}{5}

Option 4)

\frac{1}{5}

Posted by

Himanshu

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