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  • Give answer! A dielectric slab of thickness dis inserted in a parallel plate capacitor whose negative plate is at x=0and positive plate is at x=3d.The slab is equidistant from the plates. The capacitor is given some charge.As one goes from 0 to 3d.

A dielectric slab of thickness d is inserted in a parallel plate capacitor whose negative plate is at x=0 and positive plate is at x=3d. The slab is equidistant from the plates. The capacitor is given some charge. As one goes from 0 to 3d.

  • Option 1)

    The magnitude of the electric field remains the same

  • Option 2)

    The direction of the electric field remains the same

  • Option 3)

    The electric potential increases continuously

  • Option 4)

    Both b and c

 

Answers (1)

best_answer

 

As we learned

 

Infinite Plane Parallel sheets of charge -

If  

 \sigma _{A}=\sigma _{B}=\sigma \rightarrow \left | E_{p} \right |=\left | E_{R} \right |=\frac{\sigma }{\epsilon _{0}}

and  EQ = 0

-

 

 Even after introduction of dielectric slab, direction of electric field will be perpendicular to the plates and directed from positive plate to negative plate.

Further, magnitude of electric field in air =\frac{\sigma }{\varepsilon _{0}}

Magnitude of electric field in dielectric =\frac{\sigma }{K\varepsilon _{0}}

Similarly electric lines always flows from higher to lower potential, therefore, electric potential increases continuously as we move from x = 0 to x = 3d


Option 1)

The magnitude of the electric field remains the same

Option 2)

The direction of the electric field remains the same

Option 3)

The electric potential increases continuously

Option 4)

Both b and c

Posted by

Avinash

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