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  • Give answer! - A heat source at is connected to another heat heat reservoir atby a copper slab which is 1m thick - Properties of Solids and Liquids - JEE Main

A heat source at T=10^{3}K is connected to another heat heat reservoir at T=10^{2}K by a copper slab which is 1m thick. Given that the thermal conductivity of copper is 0.1 WK^{-1}m^{-1}, the energy flux through it in the steady state is:

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

Answers (1)

best_answer

 

Thermal Conductivity -

Q=\frac{KA(\theta_{1}-\theta_{2})t}{l}

K = thermal conductivity

- wherein

\left ( \frac{dQ}{dt} \right )=\frac{kA\Delta T}{l}

energy flux =

\frac{1}{A}\left ( \frac{dQ}{dt} \right )=\frac{k\Delta T}{l}=\frac{0.1\times 900}{1}=90W/m^{2}

 

 

 


Option 1)

Option 2)

Option 3)

Option 4)

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