Get Answers to all your Questions

header-bg qa

An ionic compound AB form NaCl structure where B- arrange in CCP manner and A+ occupy all octahedral voids . If atoms along a body diagonal are removed then the formula of compound is

  • Option 1)

    A5B4

  • Option 2)

    AB

  • Option 3)

    A4B5

  • Option 4)

    A3B4

 

Answers (1)

best_answer

Body diagonal contains two corners and an octahedral voids.

Number\; of\; A^{+}\; ion=6\times \frac{1}{2}+6\times \frac{1}{8}=\frac{15}{4}

Number\; of\; B^{-}\; ion=12\times \frac{1}{4}=3

A_{\frac{15}{4}}B_{3}\; \; \; or\; \; \; \; A_{5}B_{4}

 

 

Location of octahedral void -

octahedral void found at each edge centre and at body centre

- wherein

In FCC unit cell total number of octahedral voids = 4

 

 


Option 1)

A5B4

This is correct

Option 2)

AB

This is incorrect

Option 3)

A4B5

This is incorrect

Option 4)

A3B4

This is incorrect

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE