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An infinite line charge produce a field of 7.182\times 10^{8}N/C at a distance of 2 cm. The linear charge density is

  • Option 1)

    7.27\times 10^{-4}C/m

  • Option 2)

    7.98\times 10^{-4}C/m

  • Option 3)

    7.11\times 10^{-4}C/m

  • Option 4)

    7.04\times 10^{-4}C/m

 

Answers (1)

best_answer

As we learned

Linear charge distribution -

\left ( \lambda \right ) - charge per unit length.

\dpi{100} \lambda=\frac{q}{L}=\frac{C}{m}=Cm^{-1}

- wherein

wire, circulating ring ex.

 

 Relation for electric field is given by   E=\frac{\lambda }{2\pi \varepsilon _{0}r}       (Given : E = 7.182 X 108N/C)

r = 2 cm = 2 X 10-2 m

\\*\frac{1 }{4\pi \varepsilon _{0}}=9\times 10^{-9}\Rightarrow \lambda =2\pi \varepsilon _{0}rE=\frac{2\times2\pi \varepsilon _{0}rE }{2}\; \; \\*=\frac{1\times 2\times10^{-2}\times7.182\times10^{8}}{2\times9\times10^{9}}=7.98\times10^{-4}\, C/m


Option 1)

7.27\times 10^{-4}C/m

Option 2)

7.98\times 10^{-4}C/m

Option 3)

7.11\times 10^{-4}C/m

Option 4)

7.04\times 10^{-4}C/m

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Aadil

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