Get Answers to all your Questions

header-bg qa

For an elementry chemical reationA_{2}\xrightarrow[k_{-1}]{k_{1}}2A the expression for\frac{d\left [ A \right ]}{dt}  is:

 

  • Option 1)

    2k_{1}\left [ A_{2} \right ]-2k_{-1}\left [ A \right ]^{2}

  • Option 2)

    k_{1}\left [ A_{2} \right ]+2k_{-1}\left [ A \right ]^{2}

  • Option 3)

    2k_{1}\left [ A_{2} \right ]-k_{-1}\left [ A \right ]^{2}

  • Option 4)

    k_{1}\left [ A_{2} \right ]-k_{-1}\left [ A \right ]^{2}

Answers (1)

best_answer

 

Rates in presence of stoichiometry of reactants/products -

When stoichiometry coefficients of reactants/ products are not equal to one, the rate of disappearance of  & the rate of appearance of products is divided by their respective stoichiometric coefficients

- wherein

e.g.\:2HI(g)\rightarrow H_{2}(g)+I_{2}(g)

r=\frac{-1}{2}.\frac{d}{dt}[HI]

=\frac{+d}{dt}[H2]=\frac{+ d}{dt}[I_{2}]

 

 


Option 1)

2k_{1}\left [ A_{2} \right ]-2k_{-1}\left [ A \right ]^{2}

Option 2)

k_{1}\left [ A_{2} \right ]+2k_{-1}\left [ A \right ]^{2}

Option 3)

2k_{1}\left [ A_{2} \right ]-k_{-1}\left [ A \right ]^{2}

Option 4)

k_{1}\left [ A_{2} \right ]-k_{-1}\left [ A \right ]^{2}

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE