The density \left ( in\: g\: mL^{-1} \right ) of a 3.60 M sulphuric acid solution that is 29% H_{2}SO_{4}\left ( molar \: mass = 98\: g \: mol^{-1} \right ) by mass will be

  • Option 1)

    1.45

  • Option 2)

    1.64

  • Option 3)

    1.88

  • Option 4)

    1.22

 

Answers (1)
P perimeter

As we learnt in

Molarity -

Molarity = \frac{Moles \: of \: solute}{V\! ol.of\: solution(L)}

-

 

 In the givne problem 

Mass of solute = 29 gm

Mass of solution = 100 gm

Volume of solution =\frac{100}{density}ml

Molarity =\frac{Moles\ of\ solute}{Volume\ of\ solution\ in\ Litre}

M=\frac{(29/98)\times density\times 1000}{100}=3.6

Density =\frac{3.6\times 98}{29\times 10}=1.216\ gm/ml

Correct option is 4.

 


Option 1)

1.45

This is an incorrect option.

Option 2)

1.64

This is an incorrect option.

Option 3)

1.88

This is an incorrect option.

Option 4)

1.22

This is the correct option.

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