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Two point charges – Q and 2Q are separated by a distance R, neutral point will be obtained at

  • Option 1)

    A distance of \frac{R}{\sqrt2 - 1} from  – Q charge and lies between the charges

  • Option 2)

    A distance of \frac{R}{\sqrt2 - 1} from – Q charge on the left side of it 

  • Option 3)

    A distance of \frac{R}{\sqrt2 - 1} from 2Q charge on the right side of it

  • Option 4)

    A point on the line which passes perpendicularly through the centre of the line joining – Q and 2Q charge.

 

Answers (1)

best_answer

As we have learnt,

 

Neutral Point /Zero Electric Field -

Due to a system of two like Point Ooint charge.

\dpi{100} x_{1}= \frac{x}{\sqrt{\frac{Q_{2}}{Q_{1}}}+1}       ,           x_{2}= \frac{x}{\sqrt{\frac{Q_{1}}{Q_{2}}}+1}

- wherein

Where, x = distance between Q1 and Q2

 

As already we discussed neutral point will be obtained on the side of charge which is smaller in magnitude i.e. it will obtained on the left side of – Q charge and at a distance.

I = \frac{R}{\sqrt{\frac{2Q}{Q}} - 1} \Rightarrow I = \frac{R}{\sqrt2 -1} 

 


Option 1)

A distance of \frac{R}{\sqrt2 - 1} from  – Q charge and lies between the charges

Option 2)

A distance of \frac{R}{\sqrt2 - 1} from – Q charge on the left side of it 

Option 3)

A distance of \frac{R}{\sqrt2 - 1} from 2Q charge on the right side of it

Option 4)

A point on the line which passes perpendicularly through the centre of the line joining – Q and 2Q charge.

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