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  • Given below are two statements : Statement I : If the Brewster's angle for the light propagating from air to glass is θB , then the Brewster'

Given below are two statements :
Statement I : If the Brewster's angle for the light propagating from air to glass is θB , then the
Brewster's angle for the light propagating from glass to air is \frac{\pi}{2}-\theta_B

Statement II : The Brewster's angle for the light propagating from glass to air is \tan ^{-1}\left(\mu_{\mathrm{g}}\right) where \mu _{g}  is the refractive index of

glass. In the light of the above statements, choose the correct answer from the options given below

Option: 1

Both Statement I and Statement II are false


Option: 2

Statement I is true but Statement II is false


Option: 3

Statement I is false but Statement II is true


Option: 4

Both Statement I and Statement II are true


Answers (1)

best_answer

\begin{aligned} &\begin{aligned} & \mu_{\mathrm{B}} \sin \mathrm{i}_{\mathrm{B}}=1 \cdot \sin \mathrm{r} \\ & \mathrm{r}+\mathrm{i}_{\mathrm{B}}=\frac{\pi}{2} \end{aligned}\\ &\mu_{\mathrm{g}} \sin \mathrm{i}_{\mathrm{B}}=\cos \mathrm{i}_{\mathrm{B}} \Rightarrow \tan \mathrm{i}_{\mathrm{B}}=\frac{1}{\mu_{\mathrm{g}}} \Rightarrow i_{\mathrm{B}}=\tan ^{-1}\left(\frac{1}{\mu_{\mathrm{g}}}\right) \end{aligned}

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