Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Given that <img alt="\mathrm{K_{s p}} \mathrm{Cu}(\mathrm{OH})_2=1 \times 10^{-17} \mathrm{At} \; 298 \mathrm{~K}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BK_%7Bs%20p%7D%7D%

Given that \mathrm{K_{s p}} \mathrm{Cu}(\mathrm{OH})_2=1 \times 10^{-17} \mathrm{At} \; 298 \mathrm{~K} the standard reduction potential for \mathrm{Cu}^{2+} / \mathrm{Cu\ electrode} is 0.34. What will be the reduction potential at \mathrm{p H=14} for above 
Take \mathrm{\frac{2.303 \; R T}{F}=0.059 }

Option: 1

0.016 V


Option: 2

-0.16 V


Option: 3

16 V


Option: 4

-16 V


Answers (1)

best_answer

\mathrm{Cu}_{(\mathrm{aq})}^{2+}+2 \mathrm{c^{-}} \rightarrow \mathrm{Cu}(\mathrm{s})

The Red potential :-

\begin{aligned} & \mathrm{E=E^0-\frac{R T}{2 F} \ln \frac{1}{\left[\mathrm{CH}^{2+}\right]}} \\ \\& {\left[\mathrm{H}^{+}\right]=10^{-14} \mathrm{M}} \\ \\& \mathrm{{\left[\mathrm{OH}^{-}\right]=\frac{k \omega}{\left[\mathrm{H}^{+}\right]}=\frac{10^{-14} \mathrm{M}^2}{10^{-14} \mathrm{M}}=1 \mathrm{M}}} \end{aligned}

\begin{aligned} \mathrm{{\left[\mathrm{Cu}^{2+}\right]=\frac{K s p}{\left[\mathrm{OH}^{-}\right]^2} }} & =\frac{1.0 \times 10^{-17} \times \mathrm{M}^2}{1 \mathrm{M}} \\ \\& =1.0 \times 10^{-17} \mathrm{M} \end{aligned}

\begin{aligned} & \mathrm{E=0.34 \mathrm{~V}-\left(\frac{0.059 \mathrm{~V}}{2}\right) \log \frac{1}{1.0 \times 10^{-17}}} \\ \\& \mathrm{E=0.39 \mathrm{~V}-\frac{0.059 \times 17}{2}} \\ \\& \mathrm{E=0.34-0.50} \\ \\& \mathrm{ E=-0.16 \mathrm{~V}} \end{aligned}

Posted by

Riya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: NIT Rourkela cut-offs for CSE, chemical engineering drop; last years' closing ranks
anam-khan

JEE Main 2025 Live: NTA exam city slip at jeemain.nta.nic.in soon; session 1 schedule
anam-khan

JEE Main 2025 schedule out for session 1; paper 1 from January 22

Latest Question