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  • Gravitational field intensity due to a uniform disc at point '' in the given diagram is equal to - <img alt=

Gravitational field intensity due to a uniform disc at point 'P' in the given diagram is equal to -

 

 

Option: 1

\frac{2Gm}{a^2}(1-\cos\theta)


Option: 2

\frac{2Gm}{a^2}(1-\sin\theta)


Option: 3

zero


Option: 4

\frac{Gm}{a^2}(1-\cos\theta)


Answers (1)

best_answer

As we have learnt,

 

 

Gravitational field Intensity due to uniform disc -

For Uniform disc

 

 


 

\Theta \rightarrow Angle with axis

a \rightarrow Radius of disc

At the center of the disc 

I=0

At a point on its axis

I=\frac{2GM}{a^{2}}\left ( 1-\cos \Theta \right )

 

 

 

 

Posted by

mansi

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