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A proton is accelerated through 50,000 V. Its energy will increase by

  • Option 1)5000 eV
  • Option 2) (8x10-15) J
  • Option 3)5000 J
  • Option 4)50000 J
 

Answers (1)

As we have learnt,

 

when Charged Particle at rest in uniform field -

Kinetiv Energy -

K=\frac{1}{2}mv^{2}=\frac{1}{2}m\left ( \frac{QEt}{m} \right )^{2}=\frac{Q^{2}E^{2}t^{2}}{2m}

K=\frac{1}{2}m\times \frac{2Q\Delta v}{m}=Q\cdot \Delta v

-

 

  Kinetic energy K = Q.V\RightarrowK = (+e) (50000 V)
= 50000 eV = 50000 \times 1.6 \times 10–19J = 8 \times 10–15J

 

 

 


Option 1)

5000 eV

Option 2)

8 \times 10^{-15} J

Option 3)

5000 J

Option 4)

50000 J

Posted by

Vakul

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