Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me answer: - Complex numbers and quadratic equations - JEE Main-5

If  a^{2}+i\left ( 5a-6 \right )= \left ( 3a-2 \right )+i\left ( a^{2} \right ) then 'a' equals \left ( Where\; a\, \epsilon \, R \right )

  • Option 1)

    1

  • Option 2)

    2

  • Option 3)

    3

  • Option 4)

    4

 

Answers (1)

Since, complex numbers are equal so 

a^{2}=3a-2\, \Rightarrow \, a^{2}-3a+2=0\, \Rightarrow \, a=1\: or\: 2

and 5a-6=a^{2}\, \Rightarrow \, a^{2}-5a+6=0\, \Rightarrow \, a=2\: or\: 3

Both real and imaginary parts should be equal corresponding & simultaneously which will be possible when a=2

\therefore Option (B)

 

Equality in Complex Numbers -

z=x+iy & w=a+ib are equal iff x=a & y=b

- wherein

Two complex numbers are equal iff real parts as well as imaginary parts are equal.

 

 


Option 1)

1

This is incorrect

Option 2)

2

This is correct

Option 3)

3

This is incorrect

Option 4)

4

This is incorrect

Posted by

subam

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

How to crack JEE Mains 2025 in 1 month? Follow study plan, revise high-score topics, experts advice
anam-khan

IIT JEE aspirant from Bihar found hanging in Kota hostel; 17th suicide this year
anam-khan

JEE Main 2025 just a month away; section-wise preparation tips, important topics, strategies

Latest Question