Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

At $18C^{\circ}$ the conductance of $H^+$ and $CH_3COO^-$ at infinite dilution are 315 AND 35 $mho\: cm^2/eq$ . The quivalent conductivity of CH₃COOH at infinte dilution in mho cm² / eq is

Option 1)
350

Option 2)
280

Option 3)
30

Option 4)
315

Answers (1)

best_answer

As we learnt in

Conductivity -

Inverse of resistivity is called conductivity. $\kappa = \frac{1}{\rho }$

- wherein

SI unit of Conductivity = $Sm^{-1}$

$\Lambda_{\infty }\left ( H^{+} \right )=315\ mho\, \, cm^{2}\, \, eq^{-1}$

$\Lambda_{\infty }\left ( CH_{3}COO^{-} \right )=35 mho\, \, cm^{2}\, \, eq^{-1}$

Now at $\infty$ dilution , $CH_{3}COOH$ completely dissociates to $CH_{3}COO^{-}$ and $H^{+}$

$CH_{3}COOH\rightleftharpoons CH_{3}COO^{-1}+H^{+}$

$\Lambda_{\infty }\left ( CH_{3}COOH \right )=\Lambda_{\infty }\left ( CH_{3}COO^{-} \right )+\Lambda_{\infty }\left ( H^{+} \right )$

$=315+35$ mho $cm^{2}\, \, eq^{-1}$

$=350\, \, mho\, \, cm^{2}\, \, eq^{-1}$

$\therefore$ Solution is 1

Option 1)

350

Correct

Option 2)

280

Incorrect

Option 3)

30

Incorrect

Option 4)

315

Incorrect

Posted by

Aadil

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2024 application correction facility begins tomorrow; editable fields

anam-khan

BITSAT 2024 registration window closes tomorrow; exam from May 20

anam-khan

BITSAT 2024 registration deadline extended till April 16; session 1 exam from May 19 to 24

Latest Question