Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A capacitor of 20\mu F  is charged upto 500V is connected in parallel with another capacitor of 10\mu F which is charged upto 200V. The common potential is

  • Option 1)

    500V

  • Option 2)

    400V

  • Option 3)

    300V

  • Option 4)

    200V

 

Answers (1)

best_answer

As we have learned 

Common Potential -

V=\frac{Total\: charge}{Total\: capacity}=\frac{Q_{1}+Q_{2}}{C_{1}+C_{2}}

V=\frac{C_{1}V_{1}+C_{2}V_{2}}{C_{1}+C_{2}}

-

 

 

 

    By using V= \frac{C_1V_1+C_2V_2}{C_1V_2} ;  C1 = 20 mF, V1 = 500 V, C2 = 10 mF and V2 = 200 V

V= \frac{20*500+10*200}{20+10}= 400V


Option 1)

500V

Option 2)

400V

Option 3)

300V

Option 4)

200V

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 LIVE: NTA session 2 city slip soon; exam details, marking scheme, prep tips
anam-khan

JEE Main 2026: NTA reopens Session 2 registration; apply by March 13 at jeemain.nta.nic.in
anam-khan

JEE Mains 2026 LIVE: NTA session 2 city slip soon; admit card, exam dates, here's how to prepare

Latest Question