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Four wires of identical length, diameters and of the same material are streched on sonometer wire if the ratio of their tension is 1:4:9:16, then ratio of their fundamental frequencies?

  • Option 1)

    16:9:4:1

  • Option 2)

    4:3:2:1

  • Option 3)

    1:4:2:16

  • Option 4)

    1:2:3:4

 

Answers (1)

best_answer

Fundamental freq. = \frac{v}{2l}= \frac{\sqrt{\frac{T}{M}}}{2l}\Rightarrow f\propto \sqrt{T}

f= \sqrt{1:4:9:16}

 

String fixed at one end and free from other end -

f_{n}= n\frac{V}{4L}

n= 1,3,5.......

 

- wherein

f_{1}= \frac{V}{4L} is fundamental frequency

 

 


Option 1)

16:9:4:1

This is incorrect

Option 2)

4:3:2:1

This is incorrect

Option 3)

1:4:2:16

This is incorrect

Option 4)

1:2:3:4

This is correct

Posted by

divya.saini

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