A particle is moving with speed \upsilon =b\sqrt{x} along the positive x-axis. Calculate the speed of the particle at timet=\tau(assume that the particle is at the origin at t=0).

 

  • Option 1)

    \frac{b^{2}\tau}{4}

     

     

     

  • Option 2)

    \frac{b^{2}\tau}{2}

  • Option 3)

    b^{2}\tau

  • Option 4)

    \frac{b^{2}\tau}{\sqrt{2}}

Answers (1)

V=b\sqrt{x}

\frac{dx}{dt}=b\sqrt{x}

\int _{o}^{x}\frac{dx}{\sqrt{x}}=b\int ^{t}_{o}dt

2\sqrt{x}=bt

x=\frac{b^{2}t^{2}}{4}\cdots (a)

\frac{dx}{dt}=\frac{b^2t}{2}\cdots (b)

V=\frac{b^{2}\tau}{2}


Option 1)

\frac{b^{2}\tau}{4}

 

 

 

Option 2)

\frac{b^{2}\tau}{2}

Option 3)

b^{2}\tau

Option 4)

\frac{b^{2}\tau}{\sqrt{2}}

Preparation Products

Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Test Series JEE Main April 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions