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  • Help me please, In Young’s double slit experiment, the aperture screen distance is 2 m. The fringe width is 1 mm. Light of 300 nm is used. If a thin plate of glass (m = 1.5) of thickness 0.06 mm is placed over one of the slits, then there will

In Young’s double slit experiment, the aperture screen distance is 2 m. The fringe width is 1 mm. Light of 300 nm is used. If a thin plate of glass (m = 1.5) of thickness 0.06 mm is placed over one of the slits, then there will be a lateral displacement of the fringes by:

  • Option 1)

    0 cm

  • Option 2)

    5 cm

  • Option 3)

    10 cm

  • Option 4)

    15 cm

 

Answers (1)

 

Displacement of fringe -

\Delta y= \frac{D}{d}\left ( \mu -1 \right )t

Shift in position of fringes

 

- wherein

If sheet is placed in front of one of slit.

 

 Lateral displacement of fringe due to the introduction of glass plate is

\Delta y= \left ( \mu -1 \right )t \frac{D}{d}

\beta = \frac{\lambda D}{d}\Rightarrow \frac{D}{d}=\frac{\beta }{\lambda }

\Delta y= \frac{\left ( \mu -1 \right )t\beta } {\lambda }=\frac{\left ( 1.5-1 \right )\times .06mm\times 1mm}{300mm}

\frac{0.5\times 6\times 10^{-5}\times 10^{-3}}{3\times 10^{-7}}

= 0.1 m = 10cm


Option 1)

0 cm

Incorrect

Option 2)

5 cm

Incorrect

Option 3)

10 cm

Correct

Option 4)

15 cm

Incorrect

Posted by

Vakul

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