Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Two liquids X and \: Y form an ideal solution. At 300 K, vapour pressure of the solution containing 1 mol of X and 3 mol of Y is 550 mm Hg. At the same temperature, if 1 mol of Y is   further added to this solution, vapour pressure of the solution increases by 10 mm Hg. Vapour pressure (in mm Hg) of X and \: Y in their pure states will be, respectively

  • Option 1)

    200 and 300

  • Option 2)

    300 and 400

  • Option 3)

    400 and 600

  • Option 4)

    500 and 600

 

Answers (1)

best_answer

As we learnt in

Rault's Law -

The total vapour pressure of binary mixture of miscible liquids be having ideally is given by

P_{T}= P_{A}^{0}x_{A}+P_{B}^{0}x_{B}

Where x_{A}  and  x_{B} are mole fraction of A and B in liquid phase.

 

 

- wherein

P_{A}^{0}  and P_{B}^{0} are vapour pressures of pure liquids.

 

 p=p_{A}^{0}\chi_{A}+p_{B}^{0}\chi_{B}

Given that 1 mole x & 3 mole y 

\chi_{A}=\frac{1}{4},\ \; \chi_{B}=\frac{3}{4}

550=p_{A}^{0}\times \frac{1}{4}+p_{B}^{0}\times \frac{3}{4}                                        (1)

After adding 1 mole y the vapour pressure is 560 

560=p_{A}^{0}\times \frac{1}{5}+p_{B}^{0}\times \frac{4}{5}                                        (2)

By solving equation 1 & 2

p_{A}^{0}=400,\ \; p_{B}^{0}=600

Correct option is 3.

 


Option 1)

200 and 300

This is an incorrect option.

Option 2)

300 and 400

This is an incorrect option.

Option 3)

400 and 600

This is the correct option.

Option 4)

500 and 600

This is an incorrect option.

Posted by

perimeter

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 2 answer key out for BArch, BPlanning; response sheet on jeemain.nta.nic.in
anam-khan

JEE Mains 2025 Paper 2 Answer Key LIVE: BArch final answer key PDF expected soon at jeemain.nta.nic.in
anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation

Latest Question