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  • Help me please, Three charges Q, +q and -q are placed at the vertices of an equilateral triangle of side l as shown in the figure. If the net electrostatic energy of the system is zero, then Q is equal to

 Three charges Q, +q and -q are placed at the vertices of an equilateral triangle of side l as shown in the figure. If the net electrostatic energy of the system is zero, then Q is equal to 

  • Option 1) (-q/2) 
  • Option 2)-q
  • Option 3) +q
  • Option 4) Zero
 

Answers (1)

As we have learnt,

 

Potential Energy Of a System Of n Charge -

U= K\left ( \frac{Q_{1}Q_{2}}{r_{12}} +\frac{Q_{2}Q_{3}}{r_{23}}+\frac{Q_{1}Q_{3}}{r_{13}}\right )

- wherein

For system of 3 charges.

 

 Potential energy of the system

\\*U = k\frac{Qq}{l}+ k\frac{q^2}{l}+ k\frac{qQ}{l} = 0 \\*\Rightarrow \frac{kq}{l}(Q+q+Q) = 0 \Rightarrow Q = -\frac{q}{}2

 


Option 1)

\frac{-q}{2}

Option 2)

-q

Option 3)

+q

Option 4)

Zero

Posted by

Vakul

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