A body of mass 5 gm is moving at the centre with amplitude of 10 cm. Its maximum velocity is 100 cm/s. Its velocity will be 50 cm/s at a distance (in cm)

  • Option 1)

    5√2

  • Option 2)

    5√3

  • Option 3)

    10

  • Option 4)

    10√10

 

Answers (1)

As we discussed in

Relation of velocity and displacement -

v= w\sqrt{A^{2}-x^{2}}
 

- wherein

\rightarrow  x is displacement from mean position

\rightarrow  A is Amplitude.

 

 V_{max}=aw =100cms^{-1} ,\:a=10cm, \: \omega =10\:rads{-1}

\therefore v=\omega \sqrt{a^2-y^2} =50 =10\sqrt{10^2-y^2}, y=5\sqrt{3}


Option 1)

5√2

Incorrect

Option 2)

5√3

Correct

Option 3)

10

Incorrect

Option 4)

10√10

Incorrect

Most Viewed Questions

Preparation Products

Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 11999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions