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 A fully charged capacitor has a capacitance ‘C’. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity ‘s’ and mass ‘m’. If the temperature of the block is raised by ‘ DT’, the potential difference ‘V’ across the capacitance is 

  • Option 1)

    \frac{ms\Delta T}{C}

  • Option 2)

    \sqrt{\frac{2ms\Delta T}{C}}

  • Option 3)

    \sqrt{\frac{2mC\Delta T}{s}}

  • Option 4)

    \frac{mC\Delta T}{s}

 

Answers (1)

As we have learned

Potential Difference -

V=V_{0}\left ( 1-e^{\frac{-t}{Rc}} \right )

-

 

 1/2CV^2= ms\Delta T\Rightarrow V= \sqrt{\frac{2ms\Delta T}{C}}

 


Option 1)

\frac{ms\Delta T}{C}

Option 2)

\sqrt{\frac{2ms\Delta T}{C}}

Option 3)

\sqrt{\frac{2mC\Delta T}{s}}

Option 4)

\frac{mC\Delta T}{s}

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Vakul

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