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- Home
- Engineering
- Help me solve this - Electrochemistry - BITSAT
The oxidation number of sulphur in are
- Option 1)
0,1,-2
- Option 2)
2,1,-2
- Option 3)
0,1,2
- Option 4)
-2,1,-2
Answers (1)
As we learnt in
Oxidation Number -
Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belogs entirely to more electronegative elements.
-
Rules for Oxidation Number -
In all its compound, flourine has an oxidation number of -1. Other halogen (Cl, Br and I) also have oxidation number of -1, when they occur as halide ions in their compound.
- wherein
e.g. Cl, Br and I when combined with O2 have +ve oxidation number.
Rules for Oxidation Number -
The oxidation number of hydrogen is +1, except when it is bonded to metals in binary compounds (that is compound containing two elements)
- wherein
e.g. LiH,NaH and CaH2 its oxidation number is -1.
Lets take the species one by one
O.N=0
O.N=+1
O.N= - 2
Solution is 1
Option 1)
0,1,-2
Correct
Option 2)
2,1,-2
Incorrect
Option 3)
0,1,2
Incorrect
Option 4)
-2,1,-2
Incorrect
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