The oxidation number of sulphur in S_8,S_2F_2,H_2S are

  • Option 1)

    0,1,-2

  • Option 2)

    2,1,-2

  • Option 3)

    0,1,2

  • Option 4)

    -2,1,-2

 

Answers (1)

As we learnt in 

Oxidation Number -

Oxidation number denotes the oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belogs entirely to more electronegative elements.

-

 

Rules for Oxidation Number -

In all its compound, flourine has an oxidation number of -1. Other halogen (Cl, Br and I) also have oxidation number of -1, when they occur as halide ions in their compound.

- wherein

e.g. Cl, Br and I when combined with O2  have +ve oxidation number.

 

 

Rules for Oxidation Number -

The oxidation number of hydrogen is +1, except when it is bonded to metals in binary compounds (that is compound containing two elements)

- wherein

e.g. LiH,NaH and CaH2 its oxidation number is -1.

 

 Lets take the species one by one

S_{8}                          O.N=0

S_{2}F_{2}                    O.N=+1

H_{2}S                     O.N= - 2

\therefore Solution is 1


Option 1)

0,1,-2

Correct

Option 2)

2,1,-2

Incorrect

Option 3)

0,1,2

Incorrect

Option 4)

-2,1,-2

Incorrect

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