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Two metallic spheres of radii 1 cm  and 2 cm  are given charges 10^{-2 }C  and 5\times 10^{-2 }C respectively. If they are connected by a conducting wire, the final charge on the smaller sphere is           

  • Option 1)

    3* 10^{-2}C

  • Option 2)

    1* 10^{-2}C

  • Option 3)

    4* 10^{-2}C^{}

  • Option 4)

    2* 10^{-2}C

 

Answers (1)

best_answer

As we have learned

Common Potential -

V=\frac{Total\: charge}{Total\: capacity}=\frac{Q_{1}+Q_{2}}{C_{1}+C_{2}}

V=\frac{C_{1}V_{1}+C_{2}V_{2}}{C_{1}+C_{2}}

-

 

 

              Q_1= 10^{-2}C, Q_2= 5*10^{-2}C 

Total charge of the system Q = 6 ´ 10–6C

Charge on small sphere

Q'_1= \frac{Qr}{r_1+r_2}= \frac{6*10^{-2}*1}{1+2}= 2*10^{-2}C


Option 1)

3* 10^{-2}C

Option 2)

1* 10^{-2}C

Option 3)

4* 10^{-2}C^{}

Option 4)

2* 10^{-2}C

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Plabita

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