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Help me solve this - Hydrogen - JEE Main

The correct statements among (a) to (d) are :

(a) saline hydrides produce H_{2} gas when reacted with H_{2}O.

(b) reaction of LiAlH_{4} with BF_{3}  leads to B_{2}H_{6}.

(c) PH_{3} and CH_{4} are electron -rich respectively.

(d) HF and CH_{4} are called as molecular hydrides.

  • Option 1)

     (a),(b),(c) and (d).

  • Option 2)

    (c) and (d) only.

  • Option 3)

    (a),(c) and (d) only.

  • Option 4)

    (a),(b) and (c) only.

Answers (1)
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V Vakul

(a)   Saline hydride like NaH,LiH  react with water to form a base &  H_{2} gas            MH_{3}+H_{2}O(an)\rightarrow MOH(an)+H_{2}(g)

(b)   3LiAlH_{4}+4Bf_{3}\rightarrow 3Lif+3Alf_{3}+2B_{2}H_{6}

(c)  Electron-Rich Hydride - it is a type of hydrides in which the number of e^{-s} present are more than the number of e^{-} required for making octet for ex-PH_{3},NH_{3}

                               

   Electron precise hydride -is the type of hydrides in which the number of e^{s}presents is equal to the no.of e^{-s} required (octet or duplet) e_{n}-CH_{4}

                              

(d)  CH_{4},HF,H_{2}O,NH_{3} are covalent or molecular hydrides .


Option 1)

 (a),(b),(c) and (d).

Option 2)

(c) and (d) only.

Option 3)

(a),(c) and (d) only.

Option 4)

(a),(b) and (c) only.

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