# The correct statements among (a) to (d) are :(a) saline hydrides produce $H_{2}$ gas when reacted with $H_{2}O.$(b) reaction of $LiAlH_{4}$ with $BF_{3}$  leads to $B_{2}H_{6}.$(c) $PH_{3}$ and $CH_{4}$ are electron -rich respectively.(d) $HF$ and $CH_{4}$ are called as molecular hydrides.Option 1) (a),(b),(c) and (d).Option 2)(c) and (d) only.Option 3)(a),(c) and (d) only.Option 4)(a),(b) and (c) only.

(a)   Saline hydride like $NaH,LiH$  react with water to form a base &  $H_{2}$ gas            $MH_{3}+H_{2}O(an)\rightarrow MOH(an)+H_{2}(g)$

(b)   $3LiAlH_{4}+4Bf_{3}\rightarrow 3Lif+3Alf_{3}+2B_{2}H_{6}$

(c)  Electron-Rich Hydride - it is a type of hydrides in which the number of $e^{-s}$ present are more than the number of $e^{-}$ required for making octet for ex-$PH_{3},NH_{3}$

Electron precise hydride -is the type of hydrides in which the number of $e^{s}$presents is equal to the no.of $e^{-s}$ required (octet or duplet) $e_{n}-CH_{4}$

(d)  $CH_{4},HF,H_{2}O,NH_{3}$ are covalent or molecular hydrides .

Option 1)

(a),(b),(c) and (d).

Option 2)

(c) and (d) only.

Option 3)

(a),(c) and (d) only.

Option 4)

(a),(b) and (c) only.

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