If a bar magnet of magnetic moment M is kept in a uniform magnetic field B, its time period of oscillation is T. Another magnet of same length and breadth is kept in a same magnetic field. If magnetic moment of new magnet is M/4, then its oscillation time period is

  • Option 1)

    T

  • Option 2)

    2T

  • Option 3)

    T/2

  • Option 4)

    T/4

 

Answers (1)

As we discussed in concept

Time period of physical pendulum -

T= 2\pi \sqrt{\frac{I}{mgl}}

- wherein

I= moment of inertia about point of hinge

l= Seperation between point of suspension & centre of mass

 

 T=2\pi\sqrt{\frac{I}{MB}}

T^{1}\:=\:2\times 2 \pi\sqrt{\frac{I}{MB}}                                               =\:T^{1}=2T


Option 1)

T

This option is incorrect.

Option 2)

2T

This option is correct.

Option 3)

T/2

This option is incorrect.

Option 4)

T/4

This option is incorrect.

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