# If a bar magnet of magnetic moment M is kept in a uniform magnetic field B, its time period of oscillation is T. Another magnet of same length and breadth is kept in a same magnetic field. If magnetic moment of new magnet is M/4, then its oscillation time period is Option 1) T Option 2) 2T Option 3) T/2 Option 4) T/4

As we discussed in concept

Time period of physical pendulum -

$T= 2\pi \sqrt{\frac{I}{mgl}}$

- wherein

$I=$ moment of inertia about point of hinge

$l=$ Seperation between point of suspension & centre of mass

$T=2\pi\sqrt{\frac{I}{MB}}$

$T^{1}\:=\:2\times 2 \pi\sqrt{\frac{I}{MB}}$                                               $=\:T^{1}=2T$

Option 1)

T

This option is incorrect.

Option 2)

2T

This option is correct.

Option 3)

T/2

This option is incorrect.

Option 4)

T/4

This option is incorrect.

### Preparation Products

##### Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-