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  • Help me solve this The increasing order of the ionic radii of the given isoelectronic species is :

The increasing order of the ionic radii of the given isoelectronic species is :

  • Option 1)

    Cl^{-},Ca^{2+},K^{+},S^{2-}

  • Option 2)

    S^{2-},Cl^{-},Ca^{2+},K^{+},

  • Option 3)

    Ca^{2+},K^{+},Cl^{-},S^{2-}

  • Option 4)

    K^{+},S^{2-},Ca^{2+},Cl^{-}

 

Answers (4)

best_answer

As learnt in

Size of isoelectronic species -

Smaller the value of z/e, larger the size of that species.Smaller z means effective nuclear charge is small hence size is large.

-

 

 

For isoelectronic species as effective nuclear charge increases, ionic radii decreases. Nuclear charge is maximum of the species with maximum protons. Order of nuclear charge:

  


Option 1)

Cl^{-},Ca^{2+},K^{+},S^{2-}

This option is incorrect.

Option 2)

S^{2-},Cl^{-},Ca^{2+},K^{+},

This option is incorrect.

Option 3)

Ca^{2+},K^{+},Cl^{-},S^{2-}

This option is correct.

Option 4)

K^{+},S^{2-},Ca^{2+},Cl^{-}

This option is incorrect.

Posted by

Aadil

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option 3)

Posted by

vishal dange

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ca2+<k+<cl-<s2-

Posted by

SATVIK YADAV

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3

 

 

 

Posted by

hari

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