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The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes through the point (2, 3) is

  • Option 1)

    \frac{10}{3}

  • Option 2)

    \frac{3}{5}

  • Option 3)

    \frac{6}{5}

  • Option 4)

    \frac{5}{3}

 

Answers (2)

best_answer

As we learnt in

Circle touching x-axis and having radius r -

x^{2}+y^{2}\pm 2rx+2fy+f^{2}= 0

- wherein

Where f is a variable parameter.

Let\; the\; equation\; of \; the \; circle\; is \; (x-1)^{2}+(y-k)^{2}=k^{2}

It\; passes \; through\; (2,3)

\therefore \; \; \; 1+9+k^{2}-6k=k^{2}

\Rightarrow \; \; k=\frac{5}{3}\Rightarrow diameter\; =\frac{10}{3}


Option 1)

\frac{10}{3}

This option is correct.

Option 2)

\frac{3}{5}

This option is incorrect.

Option 3)

\frac{6}{5}

This option is incorrect.

Option 4)

\frac{5}{3}

This option is incorrect.

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