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For the reaction

2NO_{2(g)}\rightleftharpoons 2NO_{(g)}+O_{2(g)}

\left ( K_{c}= 1.8\times 10^{-6}\: at\: 184^{\circ}C\right )

\left ( R= 0.0831\: kJ/\left ( mol.K \right ) \right ) When  K_{p}and K_{c} are compared at 184^{\circ}C it is found that

  • Option 1)

    K_{p}\: is\: greater\: than\: K_{c}

  • Option 2)

    K_{p}\: is\: less\: than\: K_{c}

  • Option 3)

    K_{p}\: = \: \: K_{c}

  • Option 4)

    Whether \: K_{p}\: is\: greater\: than\: ;less \: than \: or\: equal\: K_{c} depends\: upon\: the\: total\: gas\: pressure\:

 

Answers (1)

best_answer

As we learnt in 

Relation between Kp and Kc -

K_{p}=K_{c}(RT)^{\bigtriangleup n}

\therefore K_{p}> K_{c}while calculating the value of Kp , pressure should be expressed in bar.

1\:bar=10^{5}pa

- wherein

\bigtriangleup n = (number of moles of gaseous products) - (number of moles gaseous reaction)

 

 2NO_{2}\left _{\left ( s \right )} \: \rightleftharpoons 2NO \: _{\left ( g \right )}+ O_{2} \: _{\left ( g \right )}

K_{c}+1.8\times 10^{-6} \: at \: 457K

K_{p}=K_{c}(RT)^{\Delta n} where \Delta n=3-2=1

K_{p}=K_{c}(0.0831\times 457)^{1}\; \; \; \; \;

K_{p}=1.8\times 10^{-6}\times (0.0831\times 457)^{1}

K_{p}=6.8\times 10^{-5}

\therefore K_{p}> K_{c}


Option 1)

K_{p}\: is\: greater\: than\: K_{c}

This option is correct

Option 2)

K_{p}\: is\: less\: than\: K_{c}

This option is incorrect

Option 3)

K_{p}\: = \: \: K_{c}

This option is incorrect

Option 4)

Whether \: K_{p}\: is\: greater\: than\: ;less \: than \: or\: equal\: K_{c} depends\: upon\: the\: total\: gas\: pressure\:

This option is incorrect

Posted by

Aadil

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