100 \; mL of a water sample contains 0.81\; g of calcium bicarbonate and 0.73\; g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of CaCO_{3} is :

(molar mass of calcium bicarbonate is 162\; g\; mol^{-1} and magnesium bicarbonate is 146\; g\; mol^{-1})
 

  • Option 1)

    100 \; ppm

  • Option 2)

    1,000 \; ppm

  • Option 3)

    10,000 \; ppm

     

  • Option 4)

    5,000 \; ppm

Answers (1)

n_{ea}CaCO_{3}=n_{ea}Ca(HCO_{3})_{2}+n_{ea}Mg(HCO_{3})_{2}

\frac{W\times2}{100}=\frac{0.81\times2}{162}+\frac{0.73\times2}{146}

w=1.0

\therefore Hardness=\frac{1.0\times10^{6}}{100}=10,000\; ppm


Option 1)

100 \; ppm

Option 2)

1,000 \; ppm

Option 3)

10,000 \; ppm

 

Option 4)

5,000 \; ppm

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