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  • Help me understand! - If the magnetic field of a plane electromagnetic wave is given by (The speed of lightm/s) then th - Electromagnetic Waves - JEE Main

If the magnetic field of a plane electromagnetic wave is given by (The speed of light =3\times 10^{8} m/s)

B=100\times 10^{-6}sin\left [ 2\pi \times 2\times 10^{15}\left ( t-\frac{x}{c} \right )\right ] then the maximum electric field associated with it is:

  • Option 1)

    6\times 10^{4}N/C

     

     

     

  • Option 2)

    3\times 10^{4}N/C

  • Option 3)

    4\times 10^{4}N/C

  • Option 4)

    4.5\times 10^{4}N/C

Answers (1)

best_answer

 

Relation between Eo and Bo -

E_{o}=c.B_{o}

- wherein

E_{o}= Electric field amplitude

B_{o} = Magnetic field amplitude

C= Speed of light in vacuum

C= speed of light 

 

 

3\times 10^{8}m/s\\\\B_{0}=100\times 10^{-6}T \\\\\\so \: we\: \: have\\\\: E_{0}=B_{0}\times C\\\\=100\times 10^{-6}\times 3\times 10^{8}\\\\E_{0}=3\times 10^{-4}N/C

 

 


Option 1)

6\times 10^{4}N/C

 

 

 

Option 2)

3\times 10^{4}N/C

Option 3)

4\times 10^{4}N/C

Option 4)

4.5\times 10^{4}N/C

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