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When an unpolarized light of intensity I_{0} is incident on a polarizing sheet, the intensity of the light which does not get transmitted is

  • Option 1)

    zero

  • Option 2)

    I_{0}

  • Option 3)

    \frac{1}{2}I_{0}

  • Option 4)

    \frac{1}{4}I_{0}

 

Answers (1)

best_answer

As we learnt in

Malus Law -

I= I_{0}\cdot \cos ^{2}\theta

\theta = angle made by E vector with transmission axis.

- wherein

I= Intensity of transmitted light after polarisation .

I_{0}= Intensity of  incident light.

 

 

 

Intensity\; of \; polarized \; light\: \; = I_{0}/2

intensity \; of\; light\; not\; transmitted \; = I_{0}-\frac{I_{0}}{2}= \frac{I_{0}}{2}

Correct option is 3.

 


Option 1)

zero

This is an incorrect option.

Option 2)

I_{0}

This is an incorrect option.

Option 3)

\frac{1}{2}I_{0}

This is the correct option.

Option 4)

\frac{1}{4}I_{0}

This is an incorrect option.

Posted by

divya.saini

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