Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Help me understand! Which one of the following alkenes when treated with HClyields majorly an anti Markovnikov product?

Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?

 

  • Option 1)

    CH_{3}O-CH=CH_{2}

  • Option 2)

    Cl-CH=CH_{2}

  • Option 3)

    H_{2}N-CH=CH_{2}

  • Option 4)

    F_{3}C-CH=CH_{2}

Answers (1)

best_answer

(1) H_{3}CO-CH=CH_{2}

H_{3}CO-- e- releasing group

 

(2) Cl-CH=CH_{2}

Cl is a deactivating group but electrons are released by the +m effect

 

(3) H_{2}N-CH=CH_{2}

H_{2}N is e- releasing group

 

(4) F_{3}C-CH=CH_{2}

F_{3}C is e- withdrawing group

Hence :- F_{3}C-CH=CH_{2}  majorly gives antimarkonikov product.


Option 1)

CH_{3}O-CH=CH_{2}

Option 2)

Cl-CH=CH_{2}

Option 3)

H_{2}N-CH=CH_{2}

Option 4)

F_{3}C-CH=CH_{2}
Posted by

solutionqc

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’
anam-khan

NIT Puducherry Cut-off 2024: Computer Science and Engineering had highest closing rank last year
anam-khan

What after JEE Main results 2024? All you need to know about JEE Adv, CSAB, JoSAA counselling

Latest Question