# Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?Option 1)$CH_{3}O-CH=CH_{2}$Option 2)$Cl-CH=CH_{2}$Option 3)$H_{2}N-CH=CH_{2}$Option 4)$F_{3}C-CH=CH_{2}$

(1) $H_{3}CO-CH=CH_{2}$

$H_{3}CO$-- e- releasing group

(2) $Cl-CH=CH_{2}$

$Cl$ is a deactivating group but electrons are released by the +m effect

(3) $H_{2}N-CH=CH_{2}$

$H_{2}N$ is e- releasing group

(4) $F_{3}C-CH=CH_{2}$

$F_{3}C$ is e- withdrawing group

Hence :- $F_{3}C-CH=CH_{2}$  majorly gives antimarkonikov product.

Option 1)

$CH_{3}O-CH=CH_{2}$

Option 2)

$Cl-CH=CH_{2}$

Option 3)

$H_{2}N-CH=CH_{2}$

Option 4)

$F_{3}C-CH=CH_{2}$

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