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  • Help me understand! Which one of the following alkenes when treated with HClyields majorly an anti Markovnikov product?

Which one of the following alkenes when treated with HCl yields majorly an anti Markovnikov product?

 

  • Option 1)

    CH_{3}O-CH=CH_{2}

  • Option 2)

    Cl-CH=CH_{2}

  • Option 3)

    H_{2}N-CH=CH_{2}

  • Option 4)

    F_{3}C-CH=CH_{2}

Answers (1)

best_answer

(1) H_{3}CO-CH=CH_{2}

H_{3}CO-- e- releasing group

 

(2) Cl-CH=CH_{2}

Cl is a deactivating group but electrons are released by the +m effect

 

(3) H_{2}N-CH=CH_{2}

H_{2}N is e- releasing group

 

(4) F_{3}C-CH=CH_{2}

F_{3}C is e- withdrawing group

Hence :- F_{3}C-CH=CH_{2}  majorly gives antimarkonikov product.


Option 1)

CH_{3}O-CH=CH_{2}

Option 2)

Cl-CH=CH_{2}

Option 3)

H_{2}N-CH=CH_{2}

Option 4)

F_{3}C-CH=CH_{2}
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