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  • How many different six-digit numbers can be formed using the digits 1, 2, 3, 4, 5, and 6, allowing repetition, where all digits are odd?  <div class='q

How many different six-digit numbers can be formed using the digits 1, 2, 3, 4, 5, and 6, allowing repetition, where all digits are odd?

 

Option: 1

405


Option: 2

729


Option: 3

325


Option: 4

242


Answers (1)

best_answer

To find the number of different six-digit numbers that can be formed using the digits 1,2,3,4,5, and 6 , allowing repetition, where all digits are odd, we need to consider the possibilities for each position in the six-digit number.

Since all digits must be odd, there are 3 choices for each position: 1,3 , or 5 . Since repetition is allowed, each position can independently choose one of the three odd digits.

Therefore, the total number of different six-digit numbers that can be formed, where all digits are odd, is

3 \times 3 \times 3 \times 3 \times 3 \times 3=729.

It is important to note that in this case, repetition is allowed and each digit can be chosen independently, resulting in a larger number of possible combinations.

Posted by

Ritika Kankaria

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