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  •  How much times the pressure of an ideal gas inside a cubic of side l is affected, if side is reduce d to l / 2 and temperature is kept instant?  <stron

 How much times the pressure of an ideal gas inside a cubic of side l is affected, if side is reduce d to l / 2 and temperature is kept instant?
 

Option: 1

9


Option: 2

8


Option: 3

4


Option: 4

6


Answers (1)

best_answer

\mathrm{ P=\frac{1}{3} \frac{m N u^2}{v}=\frac{2}{3 v}\left(\frac{1}{2} m N u^2\right)=\frac{2}{3 v}(k E) }
Temperature is constant, hence (K E) remains instant.

volume initially of side (l)=\mathrm{ l^3}

volume due to change to \mathrm{ \left(\frac{l}{2}\right)^3=\frac{l^3}{8}}

Thus, \mathrm{ P_1=\frac{2}{3} \frac{k E}{l^2}, P_2=\frac{2}{3} \frac{k E}{l^3} \times \delta }

\therefore \mathrm{ \frac{P_2}{P_1}=8 }

option (b) correct.

Posted by

Ritika Jonwal

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