Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • How to solve this problem- - A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive At a part - Electromagnetic Waves - JEE Main

A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point in space and time, \vec{E}=6.3\, \hat{j}\, \, V/m. The corresponding magnetic field \vec{B}, at that point will be :

  • Option 1)

    18.9\times 10^{-8}\, \, \hat{k}T\; \;

     

  • Option 2)

    2.1\times 10^{-8}\,\, \hat{k}T\; \;

  • Option 3)

    6.3\times 10^{-8}\,\, \hat{k}T\; \;

  • Option 4)

    18.9\times 10^{8}\,\, \hat{k}T\; \;

Answers (1)

best_answer

 

Relation between Eo and Bo -

E_{o}=c.B_{o}

- wherein

E_{o}= Electric field amplitude

B_{o} = Magnetic field amplitude

C= Speed of light in vacuum

 

\left | B \right | = \frac{\left | E \right |}{C} = \frac{6.3}{3 \times 10^{8}} = 2.1 \times 10^{-8} T

Direction \hat{E} \times \hat{B} = \hat{C}

\hat{j} \times \hat{B} = \hat{i}

\therefore \hat{B} = \hat{K}

\vec{B} = 2.1 \times 10^{-8} \hat{K}

 


Option 1)

18.9\times 10^{-8}\, \, \hat{k}T\; \;

 

Option 2)

2.1\times 10^{-8}\,\, \hat{k}T\; \;

Option 3)

6.3\times 10^{-8}\,\, \hat{k}T\; \;

Option 4)

18.9\times 10^{8}\,\, \hat{k}T\; \;

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 Exam City Slip LIVE: NTA session 2 test centre allotment soon; admit card date
anam-khan

JEE Main 2026: NTA reopens Session 2 registration; apply by March 13 at jeemain.nta.nic.in
anam-khan

JEE Mains 2026 LIVE: NTA session 2 city slip soon; admit card, exam dates, here's how to prepare

Latest Question