Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • How to solve this problem- Which one of the following aqueous solutions will exhibit highest boiling point?

Which one of the following aqueous solutions will exhibit highest boiling point?

  • Option 1)

    0.01 M\: Na_{2}SO_{4}

  • Option 2)

    0.01 M\:KNO_{3}

  • Option 3)

    0.015 M \: Urea

  • Option 4)

    0.015 M \: glucose

 

Answers (1)

best_answer

As we learnt in

Application of Vant Hoff factor -

(a)\: \: \: \left ( \frac{\Delta P}{P^{0}} \right )_{obs}= I_{solute}\times i

(b)\: \: \: \left ( \Delta T_{b} \right )_{obs}= K_{b}\times m\times i

(c)\: \: \: \left ( \Delta T_{f} \right )_{obs}= K_{f}\times m\times i

(d)\: \: \: \left ( \pi \right )_{obs}= C\times R\times T\times i

-

 

 Elevation in Boiling point \alpha\ i\times m

In 0.01 M Na2SO4 the i\times m value is 0.03 which highest in given options.

Correct option is 1.

 


Option 1)

0.01 M\: Na_{2}SO_{4}

This is the correct option.

Option 2)

0.01 M\:KNO_{3}

This is an incorrect option.

Option 3)

0.015 M \: Urea

This is an incorrect option.

Option 4)

0.015 M \: glucose

This is an incorrect option.

Posted by

perimeter

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 registration ends tomorrow; changes introduced in exam this year
anam-khan

BTech Admission 2025 Live: JEE Mains registrations closing tomorrow; VITEEE, MET exam dates out
anam-khan

JEE Main 2025 Live: NTA to close JEE registration on Friday; apply at jeemain.nta.nic.in, correction window

Latest Question