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An ideal gas occupies a volume of 2m3 at a pressure of 3 x 106 Pa. The energy of the gas is :

  • Option 1)

    9 x 106 J

  • Option 2)

    6 x 104 J

  • Option 3)

    3 x 102 J

  • Option 4)

    108 J

Answers (1)

best_answer

 

Kinetic energy of a gas due to translation per mole -

E= \frac{3}{2}PV

= \frac{3}{2}RT
 

- wherein

R = Universal gas constant

T = temperature of gasp= 3\times 10^{6}\, \, p_{a}

v=2m^{3}

E=\frac{f}{2}n\, RT=\frac{f}{2}pv

Let gas is monoatomic

f=3

E=\frac{3}{2}\times 3\times10^{6}\times2

E=9\times10^{6}J

 

 

 


Option 1)

9 x 106 J

Option 2)

6 x 104 J

Option 3)

3 x 102 J

Option 4)

108 J

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