In a Young's double slit experiment , the ratio of the slit 's width is 4:1 The ratio of the intensity of maxima to minima , close to the central fringe in the screen , will be:

  • Option 1)

    25:9

  • Option 2)

    9:1

  • Option 3)

    4:1

  • Option 4)

    \left ( \sqrt{3+1} \right )^{4}:16

     

     

     

     

     

     

     

     

     

Answers (1)

intensity\propto W

\frac{I_{1}}{I_{2}}=\frac{4}{1}

\frac{I_{max}}{I_{min}}=\frac{\left ( \sqrt{I_{1}}+\sqrt{I_{2}} \right )^{2}}{\left ( \sqrt{I_{1}}-\sqrt{I_{2}} \right )^{2}}

=\left ( \frac{\sqrt\frac{{I}_{1}}{I_{2}}+1}{\sqrt\frac{{I}_{1}}{I_{2}}-1} \right )^{2}

=\left ( \frac{\sqrt{4}+1}{\sqrt{4}-1} \right )^{2}

=\left ( \frac{2+1}{2-1} \right )^{2}

=\left ( \frac{3}{1} \right )^{2}

=\left ( \frac{9}{1} \right )


Option 1)

25:9

Option 2)

9:1

Option 3)

4:1

Option 4)

\left ( \sqrt{3+1} \right )^{4}:16

 

 

 

 

 

 

 

 

 

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