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If $(p \: \wedge \sim q) \wedge (p\wedge r) \rightarrow \sim p \vee q$ is false, then the truth values of p, q and r are, respectively :

Option 1)
F,T,F

Option 2)
T,F,T

Option 3)
T,T,T

Option 4)
F,F,F

Answers (1)

best_answer

As we learned

Truth Table of "if-then" -

-

for $\sim p\wedge q$ to be 0

pqr must be (TFT) or (TFF)

Option 1)

F,T,F

Option 2)

T,F,T

Option 3)

T,T,T

Option 4)

F,F,F

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Himanshu

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