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A circus artist is climbing from the ground along a rope, stretched from the top of vertical pole and tied at the ground. The height of the pole is 8m and the angle made by the rope with the ground level is 30^{\circ}. The distance covered by the artist in climbing to the top of the hole is 

  • Option 1)

    \frac{24\sqrt{3}}{3}m

  • Option 2)

    \frac{16\sqrt{3}}{3}m

  • Option 3)

    24m

  • Option 4)

    16m

 

Answers (1)

best_answer

As we discussed in concept

Trigonometric Ratios of Functions -

\sin \Theta = \frac{Opp}{Hyp}

\cos \Theta = \frac{Base}{Hyp}

\tan \Theta = \frac{Opp}{Base}

- wherein

Trigonometric Ratios of Functions

 

 Sin30^{\circ}\:=\:\frac{8}{OA}

\frac{1}{2}=\frac{8}{OA}

OA = 16


Option 1)

\frac{24\sqrt{3}}{3}m

This option is incorrect.

Option 2)

\frac{16\sqrt{3}}{3}m

This option is incorrect.

Option 3)

24m

This option is incorrect.

Option 4)

16m

This option is correct.

Posted by

divya.saini

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