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  • I need help with - Chemical Bonding and molecular structure - NEET

In which of the following pair both the species have sp^{3} hybridization?

  • Option 1)

    H_{2}S, BF_{3}

  • Option 2)

    SiF_{4}, BeH_{2}

  • Option 3)

    NF_{3}, H_{2}O

  • Option 4)

    NF_{3},BF_{3}

 

Answers (1)

best_answer

As we learnt in 

Dettermination of shape of molecules using VSEPR Theory -

calculate \:X

\\X=(No.\;of\:valence\:electrons\:of\:central\:atom\:)+(No.\:of\:other\:atom\:)+(Negative\:charge\:on\:the\:molecule)-(Positive\:charge\:on\:the\:molecule)

-

 

 H= \frac{1}{2}\left [ V+M+A-C \right ]

V =  valency electrons

M = no of monovalent atoms

A = anionic charge

C = Cationic charge

for NF_{3}

H= \frac{1}{2}\left [ 5+3+0-0 \right ]=4

\therefore sp^{3} hybridization

for  H_{2}O 

H=\frac{1}{2}\left [ 6+2+0-0 \right ]=4

\therefore sp^{3} hybridization


Option 1)

H_{2}S, BF_{3}

Incorrect

Option 2)

SiF_{4}, BeH_{2}

Incorrect

Option 3)

NF_{3}, H_{2}O

Correct

Option 4)

NF_{3},BF_{3}

Incorrect

Posted by

divya.saini

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