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The intensity of electric field required to balance a proton of mass 1.7\times 10^{-27}kg  and charge 1.6\times 10^{-19}C  is nearly

  • Option 1)

    1\times 10^{-7}\, V/m

  • Option 2)

    1\times 10^{-5}\, V/m

  • Option 3)

    1\times 10^{7}\, V/m

  • Option 4)

    1\times 10^{5}\, V/m

 

Answers (1)

As we learned

Electric Field Intensity -

\vec{E}=\frac{\vec{F}}{q_{0}}=\frac{kQ}{r^{2}}

- wherein

 

 Since qE=mg\; or\; E=\frac{mg}{q}=\frac{1.7\times 10^{-27}\times 9.8}{1.6\times 10^{-19}}

After solving we get ans A.

 


Option 1)

1\times 10^{-7}\, V/m

Option 2)

1\times 10^{-5}\, V/m

Option 3)

1\times 10^{7}\, V/m

Option 4)

1\times 10^{5}\, V/m

Posted by

Vakul

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