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 An electric dipole of moment p is placed at the origin along the x-axis. The electric field at a point p , whose position vector makes an angle\theta  with the x-axis, will make an angle ..... with the x-axis, where \tan \alpha = 1/2 \tan\theta

  • Option 1)

    \alpha

  • Option 2)

    \theta

  • Option 3)

    \theta+\alpha

  • Option 4)

    \theta+2\alpha

 

Answers (1)

best_answer

As we have learned

Electric Field and Potential due to an Electric Dipole -

At axial point

E_{axial}=\frac{2kpr}{\left ( r^{2}-l^{2} \right )^{2}}

V_{axial}=\frac{kP}{\left ( r^{2}-l^{2} \right )}

- wherein

 

  USE PROPERTY OF TRIANGLE

 


Option 1)

\alpha

Option 2)

\theta

Option 3)

\theta+\alpha

Option 4)

\theta+2\alpha

Posted by

Aadil

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