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  • I need help with - Limit , continuity and differentiability - JEE Main-9

Let f(x) is such that , its f'(x) = \sin x - \cos x +1  then f'(3\pi /4) equals 

  • Option 1)

    1

  • Option 2)

    \sqrt 2+1

  • Option 3)

    \sqrt 2-1

  • Option 4)

    -\sqrt 2+1

 

Answers (1)

best_answer

As we have learned

Derivative at a point -

The value of  f'(x) obtained by putting  x = a is called the derivative of  f(x) at  x = a  and it is denoted by  f'(a)  or  

\frac{dy}{dx}     at  x = a.

-

 

 \because f'(x)= \sin x-\cos x+1 so on putting x=3\pi /4  we get f'(3\pi /4) =\sin3\pi /4-\cos 3\pi /4+1=1/\sqrt2+1/\sqrt2+1= \sqrt2+1

 

 

 

 


Option 1)

1

Option 2)

\sqrt 2+1

Option 3)

\sqrt 2-1

Option 4)

-\sqrt 2+1

Posted by

Himanshu

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