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  • I need help with Positive charge Q is distributed over a circular Ring of radius a. A point particle of massm & negetive charge -q, is placed on its Axis at a distance y from the centre. Find force on particle.

Positive charge  Q is distributed over a circular Ring of radius a. A point particle of massm & negetive charge -q, is placed on its Axis at a distance y from the centre. Find force on particle.

  • Option 1)

    \frac{kQ}{a^2}

  • Option 2)

    \frac{kqyQ}{a^3}

  • Option 3)

    0

  • Option 4)

    \frac{kQy}{a^3}

 

Answers (1)

best_answer

As we have learnt,

 

E and V at a point P that lies on the axis of ring -

\dpi{100} E_{x}=\frac{kQx}{\left ( x^{2}+R^{2} \right )^{\frac{3}{2}}}  ,   V=\frac{kQ}{\left ( x^{2}+R^{2} \right )^{\frac{1}{2}}}

-

 

 As E = \frac{kQ}{(a^2 + R^2)^{\frac{3}{2}}}\Rightarrow F = qE

Putting values

F = \frac{kQqy}{a^3}

 


Option 1)

\frac{kQ}{a^2}

Option 2)

\frac{kqyQ}{a^3}

Option 3)

0

Option 4)

\frac{kQy}{a^3}

Posted by

Avinash

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