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  • I need help with Two solutions of a substance ( non electrolyte ) are mixed in the following manner. 480 ml of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture?

Two solutions of a substance ( non electrolyte ) are mixed in the following manner. 480 ml of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture?

  • Option 1)

    1.20 M

  • Option 2)

    1.50 M

  • Option 3)

    1.344 M

  • Option 4)

    2.70 M

 

Answers (1)

best_answer

As we learnt in

Molarity -

Molarity = \frac{Moles \: of \: solute}{V\! ol.of\: solution(L)}

-

 

M_{1}V_{1}+M_{2}V_{2}=M\times V_{Total}

1.5\times 480 + 1.2 \times 520 = M \times 1000

M=\frac{1344}{1000}=1.344\ M

Correct option is 3.

 


Option 1)

1.20 M

This is an incorrect option.

Option 2)

1.50 M

This is an incorrect option.

Option 3)

1.344 M

This is the correct option.

Option 4)

2.70 M

This is an incorrect option.

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