Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • I need help with When body is raised to a height equal to radius of earth, the P.E. change is

When body is raised to a height equal to radius of earth, the P.E. change is

  • Option 1) MgR
  • Option 2)MgR/2
  • Option 3)2mgR
  • Option 4) None of these
 

Answers (1)

best_answer

As we learnt in 

Gravitational Potential energy at a point -

W=-\frac{GMm}{r}

U=-\frac{GMm}{r}

U\rightarrow gravitational potential energy 

M\rightarrow Mass of source body

m\rightarrow mass of test body

r\rightarrow distance between two

- wherein

Always negative in the gravitational field because Force is attractive in nature.

 

 Potential energy = -\frac{GmM}{R}

 

at surface of earth u_{i}=-\frac{GmM}{R}

when it is raised at h-R, u_{f}=-\frac{GmM}{2R}

\therefore change\ \Delta u=u_{f}-u_{i}=\frac{GmM}{2R} = \frac{mgR}{2}


Option 1)

MgR

This is incorrect option

Option 2)

\frac{MgR}{2}

This is correct option

Option 3)

2 MgR

This is incorrect option

Option 4)

none of these

This is incorrect option

Posted by

Aadil

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2024 application correction facility begins tomorrow; editable fields
anam-khan

BITSAT 2024 registration window closes tomorrow; exam from May 20
anam-khan

BITSAT 2024 registration deadline extended till April 16; session 1 exam from May 19 to 24

Latest Question